What is the integral from-1 to 1 of (3x^2)/2 ?

The integral from-1 to 1 of (3x^2)/2 is 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of (3x^2)/2

\int_{- 1}^{1} \frac{3 x ^{2}}{2} d x

1

Solution steps

\int_{- 1}^{1} \frac{3 x ^{2}}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{3}{2} \cdot \int_{- 1}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{1}

= \frac{3}{2} [\frac{x ^{3}}{3}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{3}

= \frac{3}{2} \cdot \frac{2}{3}

Simplify

= 1

\int_{0}^{l n (2 x)} sin (6 e^{t}) d t

\int_{0}^{1} 8 t i + t j - k d t

\int_{0}^{1} sin (x^{3}) d x

\int_{0}^{π} sin^{3} (t) d t

\int_{1}^{2} x \cdot e^{- x} d x

What is the integral from-1 to 1 of (3x^2)/2 ?
The integral from-1 to 1 of (3x^2)/2 is 1