What is the integral from 1 to 2 of (2x+1/x) ?

The integral from 1 to 2 of (2x+1/x) is 3+ln(2)

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integral from 1 to 2 of (2x+1/x)

\int_{1}^{2} (2 x + \frac{1}{x}) d x

3 + ln (2)

Solution steps

\int_{1}^{2} 2 x + \frac{1}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 x d x + \int_{1}^{2} \frac{1}{x} d x

\int_{1}^{2} 2 x d x = 3

\int_{1}^{2} \frac{1}{x} d x = ln (2)

= 3 + ln (2)

\int_{0}^{2} 3^{3 x} d x

\int_{0}^{3} 2 t 4 t^{2} + 4 d t

\int_{x}^{1} 1 d x

\int_{- 1}^{3} e^{x} d x

\int_{- 3}^{4} (5 - \frac{x}{2}) d x

What is the integral from 1 to 2 of (2x+1/x) ?
The integral from 1 to 2 of (2x+1/x) is 3+ln(2)