What is the integral from 4 to 7 of 1/x ?

The integral from 4 to 7 of 1/x is ln(7)-2ln(2)

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integral from 4 to 7 of 1/x

\int_{4}^{7} \frac{1}{x} d x

ln (7) - 2 ln (2)

Solution steps

\int_{4}^{7} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{4}^{7}

Compute the boundaries:

ln (7) - 2 ln (2)

= ln (7) - 2 ln (2)

\int_{0}^{4} \frac{1}{x + 1} d x

\int_{1}^{4} 5 x d x

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\int_{- 1}^{1} (x - 1)^{3} d x

\int_{- \frac{π}{2}}^{\frac{π}{2}} cos^{4} (θ) d θ

What is the integral from 4 to 7 of 1/x ?
The integral from 4 to 7 of 1/x is ln(7)-2ln(2)