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Popular >

integral from 0 to 5 of |x^2-9|

Solution

\int_{0}^{5} x^{2} - 9 d x

Solution

\frac{98}{3}

+1

Solution steps

\int_{0}^{5} x^{2} - 9 d x

Eliminate Absolutes

= \int_{0}^{3} - x^{2} + 9 d x + \int_{3}^{5} x^{2} - 9 d x

\int_{0}^{3} - x^{2} + 9 d x = 18

\int_{3}^{5} x^{2} - 9 d x = \frac{44}{3}

= 18 + \frac{44}{3}

Simplify

18 + \frac{44}{3} : \frac{98}{3}

= \frac{98}{3}

Popular Examples

integral from 0 to 4 of 2/(1+sqrt(x))

\int_{0}^{4} \frac{2}{1 + x} d x

integral from 0 to pi/4 of (9sec^2(x))

\int_{0}^{\frac{π}{4}} (9 sec^{2} (x)) d x

integral from 0 to 3 of (y-2)(2y+1)

\int_{0}^{3} (y - 2) (2 y + 1) d y

integral from 0 to 10 of |x-7|

\int_{0}^{10} ∣ x - 7 ∣ d x

integral from 1 to e of x^4(ln(x))^2

\int_{1}^{e} x^{4} (ln (x))^{2} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 5 of |x^2-9| ?
The integral from 0 to 5 of |x^2-9| is 98/3