What is the integral from-1 to 1 of cos(2x) ?

The integral from-1 to 1 of cos(2x) is sin(2)

Popular >

integral from-1 to 1 of cos(2x)

\int_{- 1}^{1} cos (2 x) d x

sin (2)

Solution steps

\int_{- 1}^{1} cos (2 x) d x

Apply u-substitution

: \int_{- 2}^{2} cos (u) \frac{1}{2} d u

= \int_{- 2}^{2} cos (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{- 2}^{2} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{2} [sin (u)]_{- 2}^{2}

Compute the boundaries:

2 sin (2)

= \frac{1}{2} \cdot 2 sin (2)

Simplify

= sin (2)

\int_{1}^{2} 5 x (x^{2} + 1) d x

\int_{0}^{3} 10 e^{2 x} d x

\int_{0}^{1} \frac{x - 1}{x ^{2} - 2 x + 3} d x

\int_{4}^{t} \frac{12}{x} d x

\int_{0}^{1} e^{x} x^{2} d x

What is the integral from-1 to 1 of cos(2x) ?
The integral from-1 to 1 of cos(2x) is sin(2)