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Popular >

integral from 0 to 1 of (x^3+1)

Solution

\int_{0}^{1} (x^{3} + 1) d x

Solution

\frac{5}{4}

+1

Solution steps

\int_{0}^{1} x^{3} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{3} d x + \int_{0}^{1} 1 d x

\int_{0}^{1} x^{3} d x = \frac{1}{4}

\int_{0}^{1} 1 d x = 1

= \frac{1}{4} + 1

Simplify

\frac{1}{4} + 1 : \frac{5}{4}

= \frac{5}{4}

Popular Examples

integral from 0 to 1 of 2^{2x}

\int_{0}^{1} 2^{2 x} d x

integral from 0 to 3 of x/(sqrt(x^2+1))

\int_{0}^{3} \frac{x}{x ^{2} + 1} d x

integral from 6 to 12 of sqrt(3x+2)

\int_{6}^{12} 3 x + 2 d x

integral from 0 to x of arctan(x)

\int_{0}^{x} arctan (x) d x

integral from 0 to 5 of (sqrt(25-x^2))

\int_{0}^{5} (25 - x^{2}) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (x^3+1) ?
The integral from 0 to 1 of (x^3+1) is 5/4