What is the integral from 0 to 3 of 1/(x^2+1) ?

The integral from 0 to 3 of 1/(x^2+1) is arctan(3)

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integral from 0 to 3 of 1/(x^2+1)

\int_{0}^{3} \frac{1}{x ^{2} + 1} d x

arctan (3)

Solution steps

\int_{0}^{3} \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= [arctan (x)]_{0}^{3}

Compute the boundaries:

arctan (3)

= arctan (3)

\int_{e^{- 1}}^{e^{1}} ∣ ln (x) ∣ d x

\int_{1}^{3} (1 + ln (x)) x^{x} d x

\int_{\frac{1}{2}}^{1} 1 - x^{2} d x

\int_{0}^{2 - y} x d x

\int_{5}^{8} \frac{1}{x} d x

What is the integral from 0 to 3 of 1/(x^2+1) ?
The integral from 0 to 3 of 1/(x^2+1) is arctan(3)