What is the integral from 0 to 3/2 pi of sin(x) ?

The integral from 0 to 3/2 pi of sin(x) is 1

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integral from 0 to 3/2 pi of sin(x)

\int_{0}^{\frac{3}{2} π} sin (x) d x

1

Solution steps

\int_{0}^{\frac{3}{2} π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{\frac{3}{2} π}

Compute the boundaries:

1

= 1

\int_{- 1}^{3} (3 - 2 x) d x

\int_{1}^{3} cos (x) d x

\int_{0}^{π} (2 x - 1) cos (1 x) d x

\int_{1}^{0} (x^{2} - 2 x + 2) d x

\int_{0}^{4} (2 + 6 x) d x

What is the integral from 0 to 3/2 pi of sin(x) ?
The integral from 0 to 3/2 pi of sin(x) is 1