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Popular >

integral from-2 to 4 of |t^3-9t|

Solution

\int_{- 2}^{4} t^{3} - 9 t d t

Solution

\frac{93}{2}

+1

Decimal

46.5

Solution steps

\int_{- 2}^{4} t^{3} - 9 t d t

Eliminate Absolutes

= \int_{- 2}^{0} t^{3} - 9 t d t + \int_{0}^{3} - t^{3} + 9 t d t + \int_{3}^{4} t^{3} - 9 t d t

\int_{- 2}^{0} t^{3} - 9 t d t = 14

\int_{0}^{3} - t^{3} + 9 t d t = \frac{81}{4}

\int_{3}^{4} t^{3} - 9 t d t = \frac{49}{4}

= 14 + \frac{81}{4} + \frac{49}{4}

Simplify

14 + \frac{81}{4} + \frac{49}{4} : \frac{93}{2}

= \frac{93}{2}

Graph

Popular Examples

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\int_{0}^{3} 15 e^{3 x} d x

integral from 0 to 1 of (x+2)

\int_{0}^{1} (x + 2) d x

integral from 1 to 5 of xln(x)

\int_{1}^{5} x ln (x) d x

integral from 2 to 3 of sqrt(9-r^2)r

\int_{2}^{3} 9 - r^{2} r d r

integral from 0 to 9 of 8/((3+x)^2)

\int_{0}^{9} \frac{8}{( 3 + x ) ^{2}} d x

Frequently Asked Questions (FAQ)

What is the integral from-2 to 4 of |t^3-9t| ?
The integral from-2 to 4 of |t^3-9t| is 93/2