What is the integral from 0 to 6 of pi(6-z) ?

The integral from 0 to 6 of pi(6-z) is 18pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 6 of pi(6-z)

\int_{0}^{6} π (6 - z) d z

18 π

Decimal

56.54866 \dots

Solution steps

\int_{0}^{6} π (6 - z) d z

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{6} 6 - z d z

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π (\int_{0}^{6} 6 d z - \int_{0}^{6} z d z)

\int_{0}^{6} 6 d z = 36

\int_{0}^{6} z d z = 18

= π (36 - 18)

Simplify

= 18 π

\int_{1}^{5} x 2 x - 1 d x

\int_{0}^{1} (x - x^{2}) sin (nπ x) d x

\int_{1}^{x} ln (x) d x

\int_{- 1}^{0} 9 x^{2} (2 x^{3} + 5)^{2} d x

\int_{1}^{2} \frac{v ^{4} + 3 v ^{7}}{v ^{5}} d v

What is the integral from 0 to 6 of pi(6-z) ?
The integral from 0 to 6 of pi(6-z) is 18pi