What is the integral from 0 to pi/2 of 14sin(x) ?

The integral from 0 to pi/2 of 14sin(x) is 14

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi/2 of 14sin(x)

\int_{0}^{\frac{π}{2}} 14 sin (x) d x

14

Solution steps

\int_{0}^{\frac{π}{2}} 14 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 14 \cdot \int_{0}^{\frac{π}{2}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 14 [- cos (x)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= 14 \cdot 1

Simplify

= 14

\int_{1}^{2} x y d y

\int_{- 3}^{- 2} x^{2} d x

\int_{\frac{π}{2}}^{0} \frac{1 + cos ( 2 t )}{2} d t

\int_{0}^{1} \frac{1}{3} d x

\int_{2}^{4} 5 d x

What is the integral from 0 to pi/2 of 14sin(x) ?
The integral from 0 to pi/2 of 14sin(x) is 14