What is the integral from 0 to 7 of tan(y) ?

The integral from 0 to 7 of tan(y) is diverges

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integral from 0 to 7 of tan(y)

\int_{0}^{7} tan (y) d y

diverges

Solution steps

\int_{0}^{7} tan (y) d y

Take the denominator(s) of

tan (y)

and compare to zero:

y = \frac{π}{2}, y = \frac{3 π}{2}

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{\frac{π}{2}} tan (y) d y + \int_{\frac{π}{2}}^{\frac{3 π}{2}} tan (y) d y + \int_{\frac{3 π}{2}}^{7} tan (y) d y

\int_{0}^{\frac{π}{2}} tan (y) d y =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{0}^{π} \frac{1}{cos ^{2} ( x )} d x

\int_{0}^{1} π (x - x^{3})^{2} d x

\int_{- 2}^{5} ∣ t ∣ d t

\int_{e}^{e^{4}} \frac{1}{x ( ln ( x ) ) ^{3}} d x

\int_{- 2}^{0} 2 + x^{2} d x

What is the integral from 0 to 7 of tan(y) ?
The integral from 0 to 7 of tan(y) is diverges