What is the integral from 0 to 1 of 1/(2x) ?

The integral from 0 to 1 of 1/(2x) is diverges

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integral from 0 to 1 of 1/(2x)

\int_{0}^{1} \frac{1}{2 x} d x

diverges

Solution steps

\int_{0}^{1} \frac{1}{2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{1} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= \frac{1}{2} [ln ∣ x ∣]_{0}^{1}

Compute the boundaries:

diverges

= diverges

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What is the integral from 0 to 1 of 1/(2x) ?
The integral from 0 to 1 of 1/(2x) is diverges