What is (\partial)/(\partial x)(tan(3x-4y)) ?

The answer to (\partial)/(\partial x)(tan(3x-4y)) is sec^2(3x-4y)*3

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(\partial)/(\partial x)(tan(3x-4y))

\frac{\partial}{\partial x} (tan (3 x - 4 y))

sec^{2} (3 x - 4 y) \cdot 3

Solution steps

\frac{\partial}{\partial x} (tan (3 x - 4 y))

Treat

y

as a constant

Apply the chain rule:

sec^{2} (3 x - 4 y) \frac{\partial}{\partial x} (3 x - 4 y)

= sec^{2} (3 x - 4 y) \frac{\partial}{\partial x} (3 x - 4 y)

\frac{\partial}{\partial x} (3 x - 4 y) = 3

= sec^{2} (3 x - 4 y) \cdot 3

\int \frac{3}{u ^{2} + 2} d u

f (x) = (2 x - x^{2})^{3}

\frac{d}{d x} (sec^{4} (x) - tan^{4} (x))

y^{^{'}} = 3 - (2 y)

\frac{\partial}{\partial y} (ln (x^{2} + y^{3}))

What is (\partial)/(\partial x)(tan(3x-4y)) ?
The answer to (\partial)/(\partial x)(tan(3x-4y)) is sec^2(3x-4y)*3