What is the integral from-3 to 0 of (5+sqrt(9-x^2)) ?

The integral from-3 to 0 of (5+sqrt(9-x^2)) is 15+(9pi)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-3 to 0 of (5+sqrt(9-x^2))

\int_{- 3}^{0} (5 + 9 - x^{2}) d x

15 + \frac{9 π}{4}

Decimal

22.06858 \dots

Solution steps

\int_{- 3}^{0} 5 + 9 - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 3}^{0} 5 d x + \int_{- 3}^{0} 9 - x^{2} d x

\int_{- 3}^{0} 5 d x = 15

\int_{- 3}^{0} 9 - x^{2} d x = \frac{9 π}{4}

= 15 + \frac{9 π}{4}

\int_{1}^{3} \frac{2 x}{( x ^{2} + 2 ) ^{3}} d x

\int_{1}^{4} 1 + \frac{1}{x} + \frac{1}{x ^{2}} d x

\int_{0}^{1} x^{2} y d x

\int_{2}^{3} \frac{x}{2 - x ^{2}} d x

\int_{0}^{2} (x^{2} - 2 x)^{2} d x

What is the integral from-3 to 0 of (5+sqrt(9-x^2)) ?
The integral from-3 to 0 of (5+sqrt(9-x^2)) is 15+(9pi)/4