What is the integral from 1 to sqrt(3 of) 1/(x^2+1) ?

The integral from 1 to sqrt(3 of) 1/(x^2+1) is pi/(12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to sqrt(3 of) 1/(x^2+1)

\int_{1}^{3} \frac{1}{x ^{2} + 1} d x

\frac{π}{12}

Decimal

0.26179 \dots

Solution steps

\int_{1}^{3} \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= [arctan (x)]_{1}^{3}

Compute the boundaries:

\frac{π}{12}

= \frac{π}{12}

\int_{0}^{3} x + 1 d x

\int_{0}^{1} (5 - 6 x^{2}) d x

\int_{10}^{13} x x - 9 d x

\int_{- 1}^{1} \frac{9}{( x + 2 ) ^{2}} d x

\int_{1}^{4} x^{2} - 4 x + 2 d x

What is the integral from 1 to sqrt(3 of) 1/(x^2+1) ?
The integral from 1 to sqrt(3 of) 1/(x^2+1) is pi/(12)