What is the integral from 3 to 2 of sin(t) ?

The integral from 3 to 2 of sin(t) is cos(3)-cos(2)

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integral from 3 to 2 of sin(t)

\int_{3}^{2} sin (t) d t

cos (3) - cos (2)

Decimal

- 0.57384 \dots

Solution steps

\int_{3}^{2} sin (t) d t

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{2}^{3} sin (t) d t

Use the common integral:

\int sin (t) d t = - cos (t)

= - [- cos (t)]_{2}^{3}

Compute the boundaries:

- cos (3) + cos (2)

= - (- cos (3) + cos (2))

Simplify

= cos (3) - cos (2)

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What is the integral from 3 to 2 of sin(t) ?
The integral from 3 to 2 of sin(t) is cos(3)-cos(2)