What is the integral from pi/2 to 0 of (cos(x)) ?

The integral from pi/2 to 0 of (cos(x)) is -1

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integral from pi/2 to 0 of (cos(x))

\int_{\frac{π}{2}}^{0} (cos (x)) d x

- 1

Solution steps

\int_{\frac{π}{2}}^{0} cos (x) d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{\frac{π}{2}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= - [sin (x)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= - 1

\int_{0}^{l n (3)} x e^{- x} d x

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\int_{2}^{6} 4 x - 8 d x

\int_{0}^{1} u (1 - u)^{2} d u

\int_{\frac{1}{3}}^{3} (4 - \frac{4}{x ^{2}}) d x

What is the integral from pi/2 to 0 of (cos(x)) ?
The integral from pi/2 to 0 of (cos(x)) is -1