What is the integral from 0 to pi of sin(φ) ?

The integral from 0 to pi of sin(φ) is 2

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integral from 0 to pi of sin(φ)

\int_{0}^{π} sin (φ) d φ

2

Solution steps

\int_{0}^{π} sin (φ) d φ

Use the common integral:

\int sin (φ) d φ = - cos (φ)

= [- cos (φ)]_{0}^{π}

Compute the boundaries:

2

= 2

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\int_{0}^{\frac{π}{8}} sec (2 x) tan (2 x) d x

\int_{- 1}^{1} 2 x^{2} + 1 d x

\int_{10}^{15} \frac{10}{x ^{2}} d x

\int_{1}^{e} (\frac{( ln ( x ) ) ^{5}}{x}) d x

What is the integral from 0 to pi of sin(φ) ?
The integral from 0 to pi of sin(φ) is 2