What is the integral from 1 to 10 of (20)/(x^2) ?

The integral from 1 to 10 of (20)/(x^2) is 18

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 10 of (20)/(x^2)

\int_{1}^{10} \frac{20}{x ^{2}} d x

18

Solution steps

\int_{1}^{10} \frac{20}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 20 \cdot \int_{1}^{10} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{10}

= 20 [- \frac{1}{x}]_{1}^{10}

Compute the boundaries:

\frac{9}{10}

= 20 \cdot \frac{9}{10}

Simplify

= 18

\int_{0}^{2 π} - cos^{2} (t) d t

\int_{1}^{10} \frac{7}{x} d x

\int_{0}^{1} (\frac{1}{x + 1}) d x

\int_{- 2}^{1} x (x + 2) (x - 1) d x

\int_{- 2}^{2} 4 x d x

What is the integral from 1 to 10 of (20)/(x^2) ?
The integral from 1 to 10 of (20)/(x^2) is 18