What is the integral from 1 to 3 of (x+1)^4 ?

The integral from 1 to 3 of (x+1)^4 is 992/5

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integral from 1 to 3 of (x+1)^4

\int_{1}^{3} (x + 1)^{4} d x

\frac{992}{5}

Decimal

198.4

Solution steps

\int_{1}^{3} (x + 1)^{4} d x

Apply u-substitution

: \int_{2}^{4} u^{4} d u

= \int_{2}^{4} u^{4} d u

Apply the Power Rule

: [\frac{u ^{5}}{5}]_{2}^{4}

= [\frac{u ^{5}}{5}]_{2}^{4}

Compute the boundaries:

\frac{992}{5}

= \frac{992}{5}

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What is the integral from 1 to 3 of (x+1)^4 ?
The integral from 1 to 3 of (x+1)^4 is 992/5