What is the integral from 0 to r of 1/(r^2) ?

The integral from 0 to r of 1/(r^2) is diverges

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integral from 0 to r of 1/(r^2)

\int_{0}^{r} \frac{1}{r ^{2}} d r

diverges

Solution steps

\int_{0}^{r} \frac{1}{r ^{2}} d r

Apply the Power Rule

: [- \frac{1}{r}]_{0}^{r}

= [- \frac{1}{r}]_{0}^{r}

Compute the boundaries:

diverges

= diverges

\int_{0}^{\frac{1}{2}} y sin (\frac{nπ y}{2}) d y

\int_{1}^{3} 4 x^{2} d x

\int_{0}^{a} sin^{2} (\frac{nπ}{a} x) d x

\int_{- 8}^{0} y + 9 d y

\int_{- π}^{π} π^{2} - x^{2} d x

What is the integral from 0 to r of 1/(r^2) ?
The integral from 0 to r of 1/(r^2) is diverges