What is the integral from 6.3 to 6.6 of (12x^2-6x+4) ?

The integral from 6.3 to 6.6 of (12x^2-6x+4) is 139.386

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integral from 6.3 to 6.6 of (12x^2-6x+4)

\int_{6.3}^{6.6} (12 x^{2} - 6 x + 4) d x

139.386

Solution steps

\int_{6.3}^{6.6} 12 x^{2} - 6 x + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{6.3}^{6.6} 12 x^{2} d x - \int_{6.3}^{6.6} 6 x d x + \int_{6.3}^{6.6} 4 d x

\int_{6.3}^{6.6} 12 x^{2} d x = 149.796

\int_{6.3}^{6.6} 6 x d x = 11.61

\int_{6.3}^{6.6} 4 d x = 1.2

= 149.796 - 11.61 + 1.2

Simplify

= 139.386

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What is the integral from 6.3 to 6.6 of (12x^2-6x+4) ?
The integral from 6.3 to 6.6 of (12x^2-6x+4) is 139.386