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Popular >

integral from 0 to 1 of (x+x^2)

Solution

\int_{0}^{1} (x + x^{2}) d x

Solution

\frac{5}{6}

+1

Decimal

0.83333 \dots

Solution steps

\int_{0}^{1} x + x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x d x + \int_{0}^{1} x^{2} d x

\int_{0}^{1} x d x = \frac{1}{2}

\int_{0}^{1} x^{2} d x = \frac{1}{3}

= \frac{1}{2} + \frac{1}{3}

Simplify

\frac{1}{2} + \frac{1}{3} : \frac{5}{6}

= \frac{5}{6}

Graph

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\int_{1}^{4} x^{2} - 5 x + 6 d x

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\int_{\frac{1}{e}}^{1} - ln (x) d x

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\int_{1}^{3} x x - 1 d x

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\int_{3}^{6} 7 e^{y} d y

integral from 5 to 8 of 1/(x^2)

\int_{5}^{8} \frac{1}{x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (x+x^2) ?
The integral from 0 to 1 of (x+x^2) is 5/6