What is the integral from-infinity to 3 of e^{|x+1|} ?

The integral from-infinity to 3 of e^{|x+1|} is diverges

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integral from-infinity to 3 of e^{|x+1|}

\int_{- \infty}^{3} e^{∣ x + 1 ∣} d x

diverges

Solution steps

\int_{- \infty}^{3} e^{∣ x + 1 ∣} d x

Eliminate Absolutes

= \int_{- \infty}^{- 1} e^{- x - 1} d x + \int_{- 1}^{3} e^{x + 1} d x

\int_{- \infty}^{- 1} e^{- x - 1} d x =

diverges

= diverges

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What is the integral from-infinity to 3 of e^{|x+1|} ?
The integral from-infinity to 3 of e^{|x+1|} is diverges