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Popular >

integral from 1 to 2 of (2x+1)

Solution

\int_{1}^{2} (2 x + 1) d x

Solution

4

Solution steps

\int_{1}^{2} 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 x d x + \int_{1}^{2} 1 d x

\int_{1}^{2} 2 x d x = 3

\int_{1}^{2} 1 d x = 1

= 3 + 1

Simplify

= 4

Graph

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\int_{x}^{2} sin (t^{2}) d t

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\int_{0}^{x} \frac{1}{3} e^{- \frac{1}{3} t} d t

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\int_{- 2}^{1} (x^{2} - 1) d x

integral from 0 to 1 of xe^2

\int_{0}^{1} x e^{2} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (2x+1) ?
The integral from 1 to 2 of (2x+1) is 4