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Popular >

integral from 1 to 2 of (2x+5)

Solution

\int_{1}^{2} (2 x + 5) d x

Solution

8

Solution steps

\int_{1}^{2} 2 x + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 x d x + \int_{1}^{2} 5 d x

\int_{1}^{2} 2 x d x = 3

\int_{1}^{2} 5 d x = 5

= 3 + 5

Simplify

= 8

Graph

Popular Examples

integral from 0 to pi of sin(x+nx)

\int_{0}^{π} sin (x + n x) d x

integral from 0 to 2 of sqrt(x+2)-x

\int_{0}^{2} x + 2 - x d x

integral from 2 to 4 of (x-2)/(x^2-5x+4)

\int_{2}^{4} \frac{x - 2}{x ^{2} - 5 x + 4} d x

integral from-1 to 1 of 1/(sqrt(1+x^2))

\int_{- 1}^{1} \frac{1}{1 + x ^{2}} d x

integral from 2 to 5 of 1/(x^2+x-2)

\int_{2}^{5} \frac{1}{x ^{2} + x - 2} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (2x+5) ?
The integral from 1 to 2 of (2x+5) is 8