en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 6 of |3x-9|

Solution

\int_{1}^{6} ∣ 3 x - 9 ∣ d x

Solution

\frac{39}{2}

+1

Decimal

19.5

Solution steps

\int_{1}^{6} ∣ 3 x - 9 ∣ d x

Eliminate Absolutes

= \int_{1}^{3} - 3 x + 9 d x + \int_{3}^{6} 3 x - 9 d x

\int_{1}^{3} - 3 x + 9 d x = 6

\int_{3}^{6} 3 x - 9 d x = \frac{27}{2}

= 6 + \frac{27}{2}

Simplify

6 + \frac{27}{2} : \frac{39}{2}

= \frac{39}{2}

Graph

Popular Examples

integral from 1 to 2 of sqrt(1+x)

\int_{1}^{2} 1 + x d x

integral from 0 to 1 of (y+1)sqrt(1-y)

\int_{0}^{1} (y + 1) 1 - y d y

integral from 0 to 1 of (3x+5)^6

\int_{0}^{1} (3 x + 5)^{6} d x

integral from 1 to 2 of x(ln(x))^2

\int_{1}^{2} x (ln (x))^{2} d x

integral from 0 to pi/4 of e^{-2it}

\int_{0}^{\frac{π}{4}} e^{- 2 i t} d t

Frequently Asked Questions (FAQ)

What is the integral from 1 to 6 of |3x-9| ?
The integral from 1 to 6 of |3x-9| is 39/2