What is the integral from-infinity to 0 of θe^θ ?

The integral from-infinity to 0 of θe^θ is -1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to 0 of θe^θ

\int_{- \infty}^{0} θ e^{θ} d θ

- 1

Solution steps

\int_{- \infty}^{0} θ e^{θ} d θ

Compute the indefinite integral:

\int θ e^{θ} d θ = e^{θ} θ - e^{θ} + C

Compute the boundaries:

\int_{- \infty}^{0} θ e^{θ} d θ = - 1 - 0

= - 1 - 0

Simplify

= - 1

\int_{- 2}^{4} 2 x + 8 - x^{2} d x

\int_{0}^{1} x e^{x + 1} d x

\int_{x}^{1} (x + y)^{2} d y

\int_{0}^{1} x^{2} (3 + 4 x^{3})^{3} d x

\int_{0}^{2} x (x^{2} + 2)^{3} d x

What is the integral from-infinity to 0 of θe^θ ?
The integral from-infinity to 0 of θe^θ is -1