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Popular >

integral from-4 to 4 of |x+1|

Solution

\int_{- 4}^{4} ∣ x + 1 ∣ d x

Solution

17

Solution steps

\int_{- 4}^{4} ∣ x + 1 ∣ d x

Eliminate Absolutes

= \int_{- 4}^{- 1} - x - 1 d x + \int_{- 1}^{4} x + 1 d x

\int_{- 4}^{- 1} - x - 1 d x = \frac{9}{2}

\int_{- 1}^{4} x + 1 d x = \frac{25}{2}

= \frac{9}{2} + \frac{25}{2}

Simplify

\frac{9}{2} + \frac{25}{2} : 17

= 17

Graph

Popular Examples

integral from pi/(12) to pi/9 of sin(3x)

\int_{\frac{π}{12}}^{\frac{π}{9}} sin (3 x) d x

integral from 0 to 4 of |3x-6|

\int_{0}^{4} ∣ 3 x - 6 ∣ d x

integral from 3 to 7 of (sqrt(4x-12))/2

\int_{3}^{7} \frac{4 x - 12}{2} d x

integral from 0 to infinity of 1/4 (y-x)e^{-y}

\int_{0}^{\infty} \frac{1}{4} (y - x) e^{- y} d y

integral from-3 to 3 of (3+sqrt(9-x^2))

\int_{- 3}^{3} (3 + 9 - x^{2}) d x

Frequently Asked Questions (FAQ)

What is the integral from-4 to 4 of |x+1| ?
The integral from-4 to 4 of |x+1| is 17