What is the integral from x to pi of (sin(y))/y ?

The integral from x to pi of (sin(y))/y is \Si(pi)-\Si(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from x to pi of (sin(y))/y

\int_{x}^{π} \frac{sin ( y )}{y} d y

Si (π) - Si (x)

Solution steps

\int_{x}^{π} \frac{sin ( y )}{y} d y

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (y)]_{x}^{π}

Compute the boundaries:

Si (π) - Si (x)

= Si (π) - Si (x)

\int_{- π}^{π} x^{4} d x

\int_{2}^{4} 2^{4 x} d x

\int_{0}^{\frac{π}{2}} cos^{10} (x) d x

\int_{0}^{\frac{π}{4}} (4 sec^{2} (x)) d x

\int_{- 2}^{2} t^{3} (2 + t^{4})^{3} d t

What is the integral from x to pi of (sin(y))/y ?
The integral from x to pi of (sin(y))/y is \Si(pi)-\Si(x)