What is the integral from 7 to 8 of 1/x ?

The integral from 7 to 8 of 1/x is 3ln(2)-ln(7)

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integral from 7 to 8 of 1/x

\int_{7}^{8} \frac{1}{x} d x

3 ln (2) - ln (7)

Decimal

0.13353 \dots

Solution steps

\int_{7}^{8} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{7}^{8}

Compute the boundaries:

3 ln (2) - ln (7)

= 3 ln (2) - ln (7)

\int_{1}^{2} \frac{4 ( ln ( x ) ) ^{3}}{x} d x

\int_{0}^{4} (x - \frac{1}{2} x) d x

\int_{1}^{2} x (2 x^{2} - 1)^{2} d x

\int_{2}^{4} x^{4} d x

\int_{- 1}^{1} cos (\frac{nπ x}{2}) d x

What is the integral from 7 to 8 of 1/x ?
The integral from 7 to 8 of 1/x is 3ln(2)-ln(7)