What is the integral from-1 to 1 of (-2x^2+2) ?

The integral from-1 to 1 of (-2x^2+2) is 8/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of (-2x^2+2)

\int_{- 1}^{1} (- 2 x^{2} + 2) d x

\frac{8}{3}

Decimal

2.66666 \dots

Solution steps

\int_{- 1}^{1} - 2 x^{2} + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{1} 2 x^{2} d x + \int_{- 1}^{1} 2 d x

\int_{- 1}^{1} 2 x^{2} d x = \frac{4}{3}

\int_{- 1}^{1} 2 d x = 4

= - \frac{4}{3} + 4

Simplify

- \frac{4}{3} + 4 : \frac{8}{3}

= \frac{8}{3}

\int_{- 2}^{0} 2 x + 5 d x

\int_{3}^{8} \frac{1}{4 x + 4} d x

\int_{0}^{1} (4 x^{e} + 3 e^{x}) d x

\int_{0}^{\frac{π}{2}} e^{i t} d t

\int_{0}^{1} (2 - x^{2}) d x

What is the integral from-1 to 1 of (-2x^2+2) ?
The integral from-1 to 1 of (-2x^2+2) is 8/3