What is the integral from 0 to 6 of (1/(4-x)) ?

The integral from 0 to 6 of (1/(4-x)) is diverges

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integral from 0 to 6 of (1/(4-x))

\int_{0}^{6} (\frac{1}{4 - x}) d x

diverges

Solution steps

\int_{0}^{6} \frac{1}{4 - x} d x

Find undefined (singularity) points:

x = 4

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{0}^{4} \frac{1}{4 - x} d x + \int_{4}^{6} \frac{1}{4 - x} d x

\int_{0}^{4} \frac{1}{4 - x} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

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What is the integral from 0 to 6 of (1/(4-x)) ?
The integral from 0 to 6 of (1/(4-x)) is diverges