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Popular >

integral from-1 to 0 of (4x-1)

Solution

\int_{- 1}^{0} (4 x - 1) d x

Solution

- 3

Solution steps

\int_{- 1}^{0} 4 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} 4 x d x - \int_{- 1}^{0} 1 d x

\int_{- 1}^{0} 4 x d x = - 2

\int_{- 1}^{0} 1 d x = 1

= - 2 - 1

Simplify

= - 3

Popular Examples

integral from 1 to 6 of 5+sqrt(t)

\int_{1}^{6} 5 + t d t

integral from 0 to pi/2 of sin^2(u)

\int_{0}^{\frac{π}{2}} sin^{2} (u) d u

integral from 1 to 2 of 1/(x+x^2)

\int_{1}^{2} \frac{1}{x + x ^{2}} d x

integral from 1 to 8 of (\sqrt[3]{x}+1)

integral from-5 to-3 of 1/(sqrt(x^2-9))

\int_{- 5}^{- 3} \frac{1}{x ^{2} - 9} d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 0 of (4x-1) ?
The integral from-1 to 0 of (4x-1) is -3