What is the integral from 0 to 1 of 2e^{x/(3+4)}+5 ?

The integral from 0 to 1 of 2e^{x/(3+4)}+5 is 14\sqrt[7]{e}-9

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integral from 0 to 1 of 2e^{x/(3+4)}+5

\int_{0}^{1} 2 e^{\frac{x}{3 + 4}} + 5 d x

Decimal Notation

7.14990 \dots

Solution steps

\int_{0}^{1} 2 e^{\frac{x}{3 + 4}} + 5 d x

Simplify

= \int_{0}^{1} 2 e^{\frac{x}{7}} + 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 2 e^{\frac{x}{7}} d x + \int_{0}^{1} 5 d x

\int_{0}^{1} 5 d x = 5

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What is the integral from 0 to 1 of 2e^{x/(3+4)}+5 ?
The integral from 0 to 1 of 2e^{x/(3+4)}+5 is 14\sqrt[7]{e}-9