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Popular >

integral from 1 to 5 of (2x+1)

Solution

\int_{1}^{5} (2 x + 1) d x

Solution

28

Solution steps

\int_{1}^{5} 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} 2 x d x + \int_{1}^{5} 1 d x

\int_{1}^{5} 2 x d x = 24

\int_{1}^{5} 1 d x = 4

= 24 + 4

Simplify

= 28

Popular Examples

integral from-1 to 0 of-20xe^{-x}

\int_{- 1}^{0} - 20 x e^{- x} d x

integral from-3 to-1 of (-2x-3)

\int_{- 3}^{- 1} (- 2 x - 3) d x

integral from 0 to 1 of cx^2

\int_{0}^{1} c x^{2} d x

integral from 1 to 3 of ((x-1)^3)/(x^2)

\int_{1}^{3} \frac{( x - 1 ) ^{3}}{x ^{2}} d x

integral from 0 to 3 of (-x^2+2x+3)

\int_{0}^{3} (- x^{2} + 2 x + 3) d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 5 of (2x+1) ?
The integral from 1 to 5 of (2x+1) is 28