What is the integral from t to 3t of ((sin(x))/x) ?

The integral from t to 3t of ((sin(x))/x) is \Si(3t)-\Si(t)

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integral from t to 3t of ((sin(x))/x)

\int_{t}^{3 t} (\frac{sin ( x )}{x}) d x

Si (3 t) - Si (t)

Solution steps

\int_{t}^{3 t} \frac{sin ( x )}{x} d x

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (x)]_{t}^{3 t}

Compute the boundaries:

Si (3 t) - Si (t)

= Si (3 t) - Si (t)

\int_{- 2}^{1} x^{3} d x

\int_{π}^{2 π} e^{- s t} d t

\int_{2}^{3} 95 + 972 t^{2} - 18 t d t

\int_{- 1}^{1} x^{2} (1 - ∣ x ∣) d x

\int_{- 1}^{1} (x^{2} + 4) (x - 1)^{6} d x

What is the integral from t to 3t of ((sin(x))/x) ?
The integral from t to 3t of ((sin(x))/x) is \Si(3t)-\Si(t)