What is the integral from-1 to 8 of \sqrt[3]{x} ?

The integral from-1 to 8 of \sqrt[3]{x} is 45/4

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integral from-1 to 8 of \sqrt[3]{x}

\frac{45}{4}

Decimal Notation

11.25

Solution steps

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{- 1}^{8}

= [\frac{3}{4} x^{\frac{4}{3}}]_{- 1}^{8}

Compute the boundaries:

\frac{45}{4}

= \frac{45}{4}

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What is the integral from-1 to 8 of \sqrt[3]{x} ?
The integral from-1 to 8 of \sqrt[3]{x} is 45/4