en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of 2x+1

Solution

\int_{- 1}^{1} 2 x + 1 d x

Solution

2

Solution steps

\int_{- 1}^{1} 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 2 x d x + \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} 2 x d x = 0

\int_{- 1}^{1} 1 d x = 2

= 0 + 2

Simplify

= 2

Popular Examples

integral from 0 to 1 of x^3sqrt(1+3x^2)

\int_{0}^{1} x^{3} 1 + 3 x^{2} d x

integral from 0 to 2 of (x^2+3x)

\int_{0}^{2} (x^{2} + 3 x) d x

integral from 0 to 4 of (4x+sqrt(x))

\int_{0}^{4} (4 x + x) d x

integral from 1.8 to 2.4 of xe^{-x}

\int_{1.8}^{2.4} x e^{- x} d x

integral from 1 to 3 of 8x

\int_{1}^{3} 8 x d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of 2x+1 ?
The integral from-1 to 1 of 2x+1 is 2