What is the integral from-1/8 to 1/8 of (sin(2pix)) ?

The integral from-1/8 to 1/8 of (sin(2pix)) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1/8 to 1/8 of (sin(2pix))

\int_{- \frac{1}{8}}^{\frac{1}{8}} (sin (2 π x)) d x

0

Solution steps

\int_{- \frac{1}{8}}^{\frac{1}{8}} sin (2 π x) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

sin (2 π x) :

Odd

= 0

\int_{- 6}^{1} - x^{2} - 3 x d x

\int_{0}^{60} \frac{x}{2} d x

\int_{- 1}^{1} (1 - x^{2} + 1) d x

\int_{\frac{1}{12}}^{\frac{1}{4}} \frac{2}{x + 4 x x} d x

\int_{- \frac{π}{3}}^{\frac{π}{3}} sec^{2} (x) d x

What is the integral from-1/8 to 1/8 of (sin(2pix)) ?
The integral from-1/8 to 1/8 of (sin(2pix)) is 0