What is the integral from 0 to 3 of 16/3 ?

The integral from 0 to 3 of 16/3 is 16

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integral from 0 to 3 of 16/3

\int_{0}^{3} \frac{16}{3} d x

16

Solution steps

\int_{0}^{3} \frac{16}{3} d x

Integral of a constant:

\int a d x = a x

= [\frac{16}{3} x]_{0}^{3}

Compute the boundaries:

16

= 16

\int_{0}^{2} (1 - x) e^{2 x} d x

\int_{0}^{1} ln (y + 1) d y

\int_{- 3}^{2} 4 sin (x^{2}) - 1 d x

\int_{- 2}^{0} 6 x^{2} (2 x^{3} + 5)^{2} d x

\int_{- 1}^{1} 4 1 - x^{2} d x

What is the integral from 0 to 3 of 16/3 ?
The integral from 0 to 3 of 16/3 is 16