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Popular >

integral from 0 to 4 of (8-2x)

Solution

\int_{0}^{4} (8 - 2 x) d x

Solution

16

Solution steps

\int_{0}^{4} 8 - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 8 d x - \int_{0}^{4} 2 x d x

\int_{0}^{4} 8 d x = 32

\int_{0}^{4} 2 x d x = 16

= 32 - 16

Simplify

= 16

Popular Examples

integral from 0 to 3 of |3t-5|

\int_{0}^{3} ∣ 3 t - 5 ∣ d t

integral from-pi to pi of cos(n)x

\int_{- π}^{π} cos (n) x d x

integral from 1 to 5 of (z^2+4)/z

\int_{1}^{5} \frac{z ^{2} + 4}{z} d z

integral from 0.5 to 1 of x^4

\int_{0.5}^{1} x^{4} d x

integral from 0 to 2 of 12x^3+3x^2-4x

\int_{0}^{2} 12 x^{3} + 3 x^{2} - 4 x d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (8-2x) ?
The integral from 0 to 4 of (8-2x) is 16