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Popular >

integral from-1 to 1 of (x+1)

Solution

\int_{- 1}^{1} (x + 1) d x

Solution

2

Solution steps

\int_{- 1}^{1} x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x d x + \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} x d x = 0

\int_{- 1}^{1} 1 d x = 2

= 0 + 2

Simplify

= 2

Popular Examples

integral from 1 to 2 of cx^2

\int_{1}^{2} c x^{2} d x

integral from-1 to 0 of 4x^2sqrt(4x^3+6)

\int_{- 1}^{0} 4 x^{2} 4 x^{3} + 6 d x

integral from 1/2 to 1 of 1/x

\int_{\frac{1}{2}}^{1} \frac{1}{x} d x

integral from 3 to 6 of 1/(x^2)

\int_{3}^{6} \frac{1}{x ^{2}} d x

integral from pi to 2pi of sin((nx)/2)

\int_{π}^{2 π} sin (\frac{n x}{2}) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (x+1) ?
The integral from-1 to 1 of (x+1) is 2