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Popular >

integral from-1 to 0 of (6x-1)

Solution

\int_{- 1}^{0} (6 x - 1) d x

Solution

- 4

Solution steps

\int_{- 1}^{0} 6 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} 6 x d x - \int_{- 1}^{0} 1 d x

\int_{- 1}^{0} 6 x d x = - 3

\int_{- 1}^{0} 1 d x = 1

= - 3 - 1

Simplify

= - 4

Popular Examples

integral from 0 to infinity of x/(x^2+9)

\int_{0}^{\infty} \frac{x}{x ^{2} + 9} d x

integral from 2 to x of x

\int_{2}^{x} x d x

integral from 0 to t of (u^2-u+e^u)

\int_{0}^{t} (u^{2} - u + e^{u}) d u

integral from 0 to 1-x of y

\int_{0}^{1 - x} y d y

integral from 1 to 2 of (1+3x^2)/x

\int_{1}^{2} \frac{1 + 3 x ^{2}}{x} d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 0 of (6x-1) ?
The integral from-1 to 0 of (6x-1) is -4