What is the integral from-3 to 3 of sin(x^2) ?

The integral from-3 to 3 of sin(x^2) is sqrt(pi/2)\S(sqrt(2/pi)*3)-sqrt(pi/2)\S(-3sqrt(2/pi))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-3 to 3 of sin(x^2)

\int_{- 3}^{3} sin (x^{2}) d x

\frac{π}{2} § (\frac{2}{π} \cdot 3) - \frac{π}{2} § (- 3 \frac{2}{π})

Solution steps

\int_{- 3}^{3} sin (x^{2}) d x

Use the nonelementary integral:

\int sin (x^{2}) d x = \frac{π}{2} § (\frac{2}{π} x)

= [\frac{π}{2} § (\frac{2}{π} x)]_{- 3}^{3}

Compute the boundaries:

\frac{π}{2} § (\frac{2}{π} \cdot 3) - \frac{π}{2} § (- 3 \frac{2}{π})

= \frac{π}{2} § (\frac{2}{π} \cdot 3) - \frac{π}{2} § (- 3 \frac{2}{π})

\int_{r - h}^{r} π (r^{2} - x^{2}) d x

\int_{1}^{2} e^{3 t} d t

\int_{0}^{2} x + 3 d x

\int_{0}^{36} x d x

\int_{- 1}^{1} (3 - 2 x) d x

What is the integral from-3 to 3 of sin(x^2) ?
The integral from-3 to 3 of sin(x^2) is sqrt(pi/2)\S(sqrt(2/pi)*3)-sqrt(pi/2)\S(-3sqrt(2/pi))