What is the integral from 6 to 7 of 1/x ?

The integral from 6 to 7 of 1/x is ln(7)-ln(6)

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integral from 6 to 7 of 1/x

\int_{6}^{7} \frac{1}{x} d x

ln (7) - ln (6)

Decimal Notation

0.15415 \dots

Solution steps

\int_{6}^{7} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{6}^{7}

Compute the boundaries:

ln (7) - ln (6)

= ln (7) - ln (6)

\int_{1}^{7} \frac{x}{x ^{2} + 9} d x

\int_{1}^{2} (\frac{64}{3} - 8 y^{2}) d y

\int_{- 2}^{3} (5 x^{2} - 3 x - 2)^{2} d x

\int_{0}^{6} ∣ x - 2 ∣ d x

\int_{0}^{1} - x^{2} - 3 x d x

What is the integral from 6 to 7 of 1/x ?
The integral from 6 to 7 of 1/x is ln(7)-ln(6)