What is the integral from-1 to 1 of t^3(3+t^4)^3 ?

The integral from-1 to 1 of t^3(3+t^4)^3 is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of t^3(3+t^4)^3

\int_{- 1}^{1} t^{3} (3 + t^{4})^{3} d t

0

Solution steps

\int_{- 1}^{1} t^{3} (3 + t^{4})^{3} d t

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

t^{3} (3 + t^{4})^{3} :

Odd

= 0

\int_{0}^{2 \cdot π} sin (x) d x

\int_{0}^{2 π} cos^{2} (v) d v

\int_{0}^{2} (x^{2} + 4 x) d x

\int_{0}^{5} 5 x^{2} d x

\int_{0}^{3} 8 e^{2 x} d x

What is the integral from-1 to 1 of t^3(3+t^4)^3 ?
The integral from-1 to 1 of t^3(3+t^4)^3 is 0