What is the integral from 0 to 1 of x^2sqrt(x) ?

The integral from 0 to 1 of x^2sqrt(x) is 2/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of x^2sqrt(x)

\int_{0}^{1} x^{2} x d x

\frac{2}{7}

Decimal Notation

0.28571 \dots

Solution steps

\int_{0}^{1} x^{2} x d x

Simplify

x^{2} x : x^{\frac{5}{2}}

= \int_{0}^{1} x^{\frac{5}{2}} d x

Apply the Power Rule

: [\frac{2}{7} x^{\frac{7}{2}}]_{0}^{1}

= [\frac{2}{7} x^{\frac{7}{2}}]_{0}^{1}

Compute the boundaries:

\frac{2}{7}

= \frac{2}{7}

\int_{- 1}^{1} (2 - x^{2}) - (x^{2}) d x

\int_{0}^{\frac{π}{2}} 3 x cos (2 x) d x

\int_{0}^{5} \frac{x - 1}{x + 1} d x

\int_{5}^{7} x^{2} + x - 14 d x

\int_{1}^{x^{2}} sin (t^{2} - 1) d t

What is the integral from 0 to 1 of x^2sqrt(x) ?
The integral from 0 to 1 of x^2sqrt(x) is 2/7