Solution
Solution
Solution steps
Apply u-substitution
Take the constant out:
Use the common integral:
Compute the boundaries:
Popular Examples
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Frequently Asked Questions (FAQ)
What is the integral from 63 to x of 1/(1050-30x) ?
The integral from 63 to x of 1/(1050-30x) is -1/30 (ln|1050-30x|-ln(840))